Collection
Async ready, chainable, highly convenient array subclass. Supports all array methods, plus a bunch of async iterations and some common Lodash methods out of the box.
Requirements
-
node >= 8.6
, tested with:node@8.6.0
node@12.8.1
-
typescript >= 4.0
, tested with:typescript@4.0.2
Installation
npm i @bluejay/collection [--save]
Usage
Array inheritance
A Collection
IS an Array
. Collections are fully compatible with the ES6 array specification.
In practice:
const collection = new Collection([1, 2, 3]);
Array.isArray(collection); // true
function foo(bar: number[]) {
// Do stuff
}
foo([1, 2, 3]); // Compiles
foo(collection); // Compiles too!
JSON.stringify(collection); // [1,2,3]
Array.from(collection); // [1,2,3]
If you wish to check if an object is a collection, use Collection.isCollection()
:
const collection = new Collection([1, 2, 3]);
Collection.isCollection(collection); // true
Available methods
- All array methods are supported
- Some
Lodash
methods such asomit()
orpick()
are built-in as instance methods - A few async methods allow you to perform async operations directly from the collection itself
import { Collection } from '@bluejay/collection';
const collection = new Collection([{ foo: 1 }, { foo: 2 }, { foo: 3 }]); // Initialize with an array
collection.size(); // 3
collection.getAt(1); // { foo: 2 }
collection.setAt(1, 5);
// Array style elements access
collection[1] = { foo: 18 };
collection[1]; // { foo: 18 }
// Regular array methods
collection.forEach(el => console.log(el.foo)); // 1, 2, 3
collection.map(el => console.log(el.foo)); // 1, 2, 3
// Async array methods
await collection.mapSeries(async el => el.foo * 2); // Collection<[2, 4, 6]>
await collection.mapParallel(async el => el.foo * 2); // Collection<[2, 4, 6]>
// Lodash methods
collection.findByProperties({ foo: 1 }); // { foo: 1 }
collection.mapByProperty('foo'); // Collection<[1, 2, 3]>
// Iterate
for (const object of collection) {
// Do something
}
Collections and inheritance
To create a Collection subclass, just do what you do best:
class MyCollection<T> extends Collection<T> {
private persistent:
public constructor(objects: T[], options: { persistent: boolean }) {
super(objects);
this.persistent = options.persistent;
}
public isPersistent() {
return this.persistent;
}
}
const instance = new MyCollection([1, 2, 3], { persistent: true });
instance.size(); // 3
instance.isPersistent(); // true
You will, however, soon notice that methods that return a collection return an instance of Collection
, not MyCollection
.
const filtered = instance.filter(value => value >= 2);
filtered.toArray(); // [2, 3]
filtered.isPersistent(); // Compilation error! `isPersistent()` does not exist on type `Collection`
This is because Bluejay has no way to know which arguments your implementation requires. In order to solve this issue, we need to override the factory()
method which Bluejay calls each time it needs to create a new Collection.
class MyCollection<T> extends Collection<T> {
private persistent:
public constructor(objects: T[], options: { persistent: boolean }) {
super(objects);
this.persistent = options.persistent;
}
protected factory<Y>(objects: Y[]) { // We don't know which type exactly we're getting here since `map()` and other methods might create collections of a different type than T
return new MyCollection<Y>(objects, { persistent: this.persistent });
}
public isPersistent() {
return this.persistent;
}
}
const instance = new MyCollection([1, 2, 3], { persistent: true });
instance.isPersistent(); // true
const filtered = instance.filter(value => value >= 2);
filtered.isPersistent(); // true - Not compilation error anymore
instance.forEach((value, index, currentObj: MyCollection<number>) => { // Note that we need to explicitly set the type here as TS doesn't manage to infer it from the implementation
currentObj.isPersistent(); // true
});
Note: While we made sure to provide a way for you to override the instances created by Bluejay, most implementations will not need such a complex setup. It is absolutely NOT necessary to override this method if you don't explicitly need to.