npm i compare-anything
Compares objects and arrays and tells you which props or values are duplicates, and which are only present once.
It works just like you would compare two columns in excel! But who needs excel when you've got JavaScript, am I right? 😃
- is-what 🙉
- is-where 🙈
- merge-anything 🥡
- check-anything 👁
- remove-anything ✂️
- getorset-anything 🐊
- map-anything 🗺
- filter-anything ⚔️
- copy-anything 🎭
- case-anything 🐫
- flatten-anything 🏏
- nestify-anything 🧅
It works just like you would expect. You compare(objectA, objectB)
and it gives you all kind of info.
You can do all kind of things with compare-anything!
- Compare object props, to see which props are present in which objects
Which props are present in which objects. Remember, this function only looks at the prop-names! Not the values.
Will return an info object with:
-
props
- an array with all props of all objects -
presentInAll
- is the prop present in all passed objects?true
/false
per prop -
perProp
- an array of objects per prop that had that specific prop -
presentIn
- an array of indexes per prop that had that specific prop (indexes of the params you passed to the function)
import { compareObjectProps } from 'compare-anything'
// only props 'b' and 'c' are present in both ↓
const objectA = {a: '🎴', b: '🎴', c: '🎴'}
const objectB = {b: '🀄️', c: '🀄️', d: '🀄️'}
compareObjectProps(objectA, objectB)
// returns ↓
{
props: ['a', 'b', 'c', 'd'],
presentInAll: { a: false, b: true, c: true, d: false },
perProp: { a: [objectA], b: [objectA, objectB], c: [objectA, objectB], d: [objectB] },
presentIn: { a: [0], b: [0, 1], c: [0, 1], d: [1] }
}
You can pass as many arguments as you want!
// keep on adding objects to compare!
compareObjectProps(objectA, objectB, objectC, objectD, objectE)
When you need to compare objects in an array you can use destructuring:
// you can compare an array of objects like so:
compareObjectProps(...objectArray)
When you need to find duplicate objects based on one single prop value of that object, you can easily do so as follows:
compareObjectProps(
...arrayOfObjects.map(obj => {
return { [obj.idField]: obj }
})
)
In the example above you can change idField
by the actual prop name you need. By making a key out of the value you can easily find duplicates based on just this field.
If we require to check even nested props we can use the flatten-anything function like shown below:
import flatten from 'flatten-anything'
import { compareObjectProps } from 'compare-anything'
const objectA = {nested: {a: '🎴', b: '🎴'}}
const objectB = {nested: {a: '🀄️', c: '🀄️'}}
const flatA = flatten(objectA)
// → {'nested.a': '🎴', 'nested.b': '🎴'}
const flatB = flatten(objectB)
// → {'nested.a': '🀄️', 'nested.c': '🀄️'}
compareObjectProps(flatA, flatB)
// returns ↓
{
props: ['nested.a', 'nested.b', 'nested.c'],
presentInAll: { 'nested.a': true, 'nested.b': false, 'nested.c': false },
perProp: { 'nested.a': [objectA, objectB], 'nested.b': [objectA], 'nested.c': [objectB] },
presentIn: { 'nested.a': [0, 1], 'nested.b': [0], 'nested.c': [1] }
}