myanimelist-url-to-id

MyAnimeList Url to ID Parser/Converter

Convert your MyAnimeList URL to the respective's object ID. This can be usefull when you're trying to parse MyAnimeList URl's to extract their ID.

Yes, we support TypeScript.

Supported Url

• Anime
• Manga
• Character (Both Manga and Anime)

Usage

Installation

npm i -s myanimelist-url-to-id

# OR

yarn add myanimelist-url-to-id

Use them in your project

import { getCharaId } from 'myanimelist-url-to-id';

console.log(getCharaId('https://myanimelist.net/character/81239/Yuuma_Kuga'));
// 81239

Documentation

You can actually see the usage of this library on the __test__folder, and go with the documentation that I made on the functions comment (that shows up on Intellisense). But for clarity I'll write it here too.

AnimeUtil Class

getAnimeId (url: string): number

Will returns something like 34599

getAnimeUrl (id: number): string

Will return something like https://myanimelist.net/anime/34599

CharaUtil Class

Note: Chara stands for Character.

getCharaId(url: string): number

Will return something like 140046

getCharaUrl(id: number): string

Will return something like https://myanimelist.net/character/140046

MangaUtil Class

getMangaId(url: string): number

Will return something like 91941

getMangaUrl(id: number): string

Will return something like https://myanimelist.net/manga/91941

InvalidUrl Exception

the getAnimeId, getCharaId and getMangaId will throws InvalidUrl exception when the Url doesn't match the pattern we have. Please handle it properly.

import {InvalidUrl} from "myanimelist-url-to-id/build/exceptions"
try {
	let animeId = getAnimeId('malformed-url'); 
} catch (e) {
    if(e instanceof InvalidUrl) {
        // handle your error here.
    }
}

FAQ

Do this library requires MAL API?
Short answer — No. We just parse your url and give you back the ID.

Do I need to access MAL API to get the full information?
Yes.

How can this be an FAQ when you wrote it before the package released?
In this case, "FAQ" stands for "Fully Anticipated Questions".

License

MIT.